(5^2x-3)=(7^x+1)

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Solution for (5^2x-3)=(7^x+1) equation: 



(5^2x-3)=(7^x+1)

We move all terms to the left:

(5^2x-3)-((7^x+1))=0

We get rid of parentheses

5^2x-((7^x+1))-3=0



We calculate terms in parentheses: -((7^x+1)), so:

(7^x+1)

We get rid of parentheses

7^x+1

Back to the equation:

-(7^x+1)



We get rid of parentheses

5^2x-7^x-1-3=0

We add all the numbers together, and all the variables

5^2x-7^x-4=0

We move all terms containing x to the left, all other terms to the right

5^2x-7^x=4

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